Processing math: 100%

Math 317: Homework 11

Due: Friday, May 3, 2019
  1. (34.4) Let f be the function,

    f(t)={tt<0t2+10t20t>2
    1. Determine the function F(x)=x0f(t)dt.

    2. Sketch F. Where is F continuous?

    3. Where is F differentiable? Calculate F at the points of differentiability.

    1. F(x)={t2t<0t3/3+t0t214/3t>2
    2. By the FTC II, F(x) is continuous everywhere.

    3. By the FTC II, F(x) is differentiable everywhere that f(x) is continuous, hence at all x except possibly x=0 and x=2.

      We can prove that F(x) is not differentiable at x=0 and x=2 by showing that the left-hand and right-hand difference quotient limits disagree.

  2. (34.6) Let f be a continuous function on R and define

    F(x)=sinx0f(t)dtfor xR.

    Show that F is differentiable on R and compute F.

    Let G(x)=x0f(t)dt. Then G(x) is differentiable and G(x)=f(x) by the FTC II as f is continuous. Notice that F(x)=G(sinx). So by the chain rule, F is differentiable and F(x)=G(sinx)cosx=f(sinx)cosx.

  3. (34.11) Suppose f is a continuous function on [a,b]. Show that if baf(x)2dx=0, then f(x)=0 for all x[a,b].

    Proof: We have that f2(x)0 and f2(x) is continuous as f is, so by Theorem 33.4(ii) f2(x)=0. By factoring, this is only possible if f(x)=0.

  4. (34.12) Show that if f is a continuous real-valued function on [a,b] satisfying baf(x)g(x)dx=0 for every continuous function g on [a,b], then f(x)=0 for all x[a,b].

    Proof. As the statement is true for all g, it is true for g=f. Then this is true by question (3).

  5. For this problem, you may use the results of questions (3) and (4) freely. Let C([a,b]) be the set of all continuous functions on the interval [a,b]. Define a function

    ,:C([a,b])×C([a,b])R

    by,

    f,g=bafg
    1. Let f,g,hC([a,b]). Show that , is an inner product. That is, show each of:

      • f,g=g,f.

      • af,g=af,g.

      • f+h,g=f,g+h,g.

      • f,f=0 if and only if f=0.

    2. Let fC([a,b]). Show that if f,g=0 for all gC([a,b]), then f=0. In other words, you are showing that the only function orthogonal to all other functions with this inner product is the zero function.

      • By commutativity of function multiplication.
      • By linearity of the integral.
      • By linearity of the integral.
      • By the result of question (3)
    1. By the result of question (4).